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in Sets, relations and functions by (20 points)
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Let f : R → [ 2 , ∞ ) be a function defined as f ( x ) = x2 − 12 ax + 15 − 2 a + 36a2 . If f ( x ) is surjective on R, then the value of a is

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Rewriting the given function, we get,

f(x) = (x - 6a)2 + 15 - 2a

\(\because\) f (x) is surjective on R 

⇒ 15 - 2a = 2 

⇒ 2a = 13 

⇒ a = 13/2

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