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Bond angle in PH4+ is higher than that in PH3 Why?

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In PH3 , P is sp3 hybridized. Three orbitals are involved in bonding with three hydrogen atoms and the fourth one contains a lone pair. As lone pair-bond pair repulsion is stronger than bond pair-bond pair repulsion, the tetrahedral shape associated with sp3 bonding is changed to pyramidal. PH3 Combines with a proton to form PH4+, in which the lone pair is absent. Due to the absence of lone pair in PH4+, there is no lone pair-bond pair repulsion.

Hence, the bond angle in PH4+ is higher than the bond angle in is PH3

PH4+

PH3

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