((a^2-b^2)^3 + (b^2-c^2)^3 + (c^2-a^2)^3)/((a-b)^3 + (b-c)^3 + (c-a)^3) on simplification is equal to :

Question

\(\frac{(a^2-b^2)^3+(b^2-c^2)^3 + (c^2-a^2)^3}{(a-b)^3+(b-c)^3+(c-a)^3}\) on simplification is equal to :

(a) 1 

(b) (a – b) (b – c) (c – a) 

(c) (a + b) (b + c) (c + a) 

(d) 0

Answer 1

(c) (a + b) (b + c) (c + a) 

Use the identity, if a + b + c = 0, then a³ + b³ + c³ = 3abc.