Let us first write down the first 2 terms which are 1, 1.
To find the remaining terms, we use the general formula. F(n) = F(n – 1) + F(n – 2)
∴ F(3) = F(2) + F(1)
F(1) = 1; F(2) = 1
F(3) = 1 + 1=2
F(4) = F(3) + F(2) = 2 + 1 = 3
F(5) = F(4) + F(3) = 2 + 3 = 5
∴ The first 10 terms are; 1, 1, 2, 3, 5, 8,13, 21, 34, 55
