N2(g) + 3H2(g) → 2NH3(g)
\(\because\) 28 kg of N2 react with 6 kg of H2
\(\therefore\) 50 kg of N2 will react with = \(\frac{6}{28}\) x 50 = \(\frac{300}{28}\) = 10.71 kg of H2
\(\because\) H2 is present in small amount, so H2 is the limiting reagent.
Now, \(\because\) 6 kg H2 give 2 × 17 kg of NH3
\(\because\) 10 kg H2 will give = \(\frac{2\times17\times10}{6}\) = 56.66 kg of NH3