(b) - 3
Hint.
Since \({4\sqrt[3]{4^2}}\) = 22.(24)\(^{\frac{1}{3}}\)= \(2^{2+\frac{4}{3}}\) = \(2^{\frac{10}{3}}\) and
1024 = 210, therefore,
log\(_{4.\sqrt[3]{4^2}}\) \(\bigg(\frac{1}{1024}\bigg)\) = log210/3 (2-10) = \(\frac{-10}{\frac{10}{3}}\) log2 2
= – 3 × 1 = – 3. \(\bigg[\)Using loga xm = \(\frac{m}{n}\) loga x\(\bigg].\)