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0 votes
1.6k views
in Logarithm by (23.6k points)

log\(_{4\sqrt[3]{4^2}}\) \(\bigg(\frac{1}{1024}\bigg)\) is equal to

(a) – 5 

(b) – 3 

(c) 3 

(d) 5

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1 Answer

+1 vote
by (24.0k points)

(b) - 3

Hint. 

Since \({4\sqrt[3]{4^2}}\) = 22.(24)\(^{\frac{1}{3}}\)\(2^{2+\frac{4}{3}}\) = \(2^{\frac{10}{3}}\) and 

1024 = 210, therefore,

log\(_{4.\sqrt[3]{4^2}}\) \(\bigg(\frac{1}{1024}\bigg)\) = log210/3 (2-10) = \(\frac{-10}{\frac{10}{3}}\) log2 2

= – 3 × 1 = – 3. \(\bigg[\)Using logx\(\frac{m}{n}\) loga x\(\bigg].\)

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