Sol;:

**Steps of construction:**

1. Draw a line segment XY of 6.4cm.

2. Draw ∠DXY = B = 60^{o} and ∠EYX =∠C = 45^{o}

3. Draw the angle bisector of ∠DXY and ∠EYX which interest each other at A.

4. Draw the perpendicular bisector of AX and AY which interest XY at B and C respectively.

5. Join AB and AC

Therefore ΔABC is the required triangle.