a) In the complex ion [Ni(CN)4]2 the central metal atom Ni is in +2 oxidation state and has the electronic configuration 3d8. Since CN – is a strong field ligand two unpaired electrons are forced to pair up against Hund’s rule and makes available a vacant 3d, one 4s and two 4p orbitals, which hybridise to give four dsp2 hybrid orbitals. Each of the hybrid orbitals receives a pair of electrons from a cyanide ion to form [Ni(CN)4]2-. Since there is no unpaired electron, the complexion is diamagnetic.
Since the hybridisation involved is dsp2 this complex has a square planar geometry.
b) i) In [Ni(CO)4] the central atom Ni undergoes sp3 hybridisation. Hence, it has a tetrahedral geometry. In [CoF6]3 the central metal ion Co3+ is in the sp3d2 hybridised state. Hence, it has an octahedral geometry,
ii) [Co(NH3)5Br]2+
OR
Pentaamminebromidocobalt(lll) ion