# In the given figure, OACB is a quadrant of circle with centre O and radius 3.5 cm. If OD = 2 cm,

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In the given figure, OACB is a quadrant of circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the [Use π = 22/7]

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(i) Since OACB is a quadrant, it will subtend 90° angle at O.

Area of quadrant OACB = 90o/360o x πr2

(ii) Area of ΔOBD = 1/2 OB x OD

= 1/2 x 3.5 x 2

= 7/2

Area of the shaded region = Area of quadrant OACB − Area of ΔOBD