Sarthaks Test
0 votes
2.9k views
in Mathematics by (11.0k points)

In the given figure, OACB is a quadrant of circle with centre O and radius 3.5 cm. If OD = 2 cm, find the area of the [Use π = 22/7]

(i) Quadrant OACB   

(ii) Shaded region 

1 Answer

0 votes
by (18.2k points)
selected by
 
Best answer

(i) Since OACB is a quadrant, it will subtend 90° angle at O.

Area of quadrant OACB = 90o/360o x πr2 

(ii) Area of ΔOBD = 1/2 OB x OD

                             = 1/2 x 3.5 x 2

                             = 7/2

Area of the shaded region = Area of quadrant OACB − Area of ΔOBD

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...