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If A = \(\begin{bmatrix} 2 & -3 & 5 \\ 3 & 2 & -4 \\ 1 & 1 & -2 \end{bmatrix} \)

1.Find A-1 

2. Using it solve the system of equations 2x – 3y + 5z = 16, 3x + 2y – 4z = -4, x + y – 2z = -3 

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1. A = \(\begin{bmatrix} 2 & -3 & 5 \\ 3 & 2 & -4 \\ 1 & 1 & -2 \end{bmatrix} \)

⇒ |A| = 0 + 3x - 2 + 5 = -1

2. Given; 

AX = B
⇒ X = A-1B

⇒ x = 2, y = 1, z = 3.

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