Given,
Total momentum = (18 kgm/s)\(\hat{I},\)
Velocity of centre of mass = (3 m/s)\(\hat{I},\)
Mass of one object = 4 kg,
Velocity of the objet = (1.5 m/s)\(\hat{I},\)
Let m be the mass of other object and be the velocity.
Now we know total momentum = Total mass × velocity of centre of mass
(18 kgm/s)\(\hat{I},\)= ( + 4)(3 m/s)\(\hat{I},\)
or m = 2 kg
Now, vcm = \(\frac{m_1v_1+m_2v_2}{m_1+m_2}\)
Or, 3i = (4×1.5i + 2v)/6
So, 18i = 6i + 2v
Or, v = 6i m/s.