Question

Two bodies of unequal mass are moving in the same direction with equal kinetic energy. The two bodies are brought to rest by applying retarding force of same magnitude. How would the distance moved by them before coming to rest compare?

Answer 1

By work energy theorem, work done is equal to charge in K.E.

Both bodies has same K.E. and hence same amount of work is needed to be done. Since force applied is same, they would come to rest within the same distance.