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in Integrals by (28.2k points)
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Match the following.

A B
\(\int{\frac{1}{x^2-9}}dx\) \(\frac{e^{3x}}{3}+c\)
\(\int secx(secx+ tanx)dx\) secx. tanx +c
secx + tanx +c
\(\int e^{3x}dx\) \(\frac{1}{6}log|\frac{x-3}{x+3}|+c\)
\(\int (sinx + cosx)dx\) sinx - cosx +c

1 Answer

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by (28.9k points)
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Best answer

1. 

2. ∫sec x(sec x + tan x)dx = ∫(sec2 x + sec x. tan x)dx
= tanx + secx + c.

3. ∫e3xdx = \(\frac{e^{3x}}{3}+c\).

4. ∫(sin x + cos x)dx = sin x – cosx + c.

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