Question

Solve 3 – 2x < 9, when x ∈ R. Express the solution in the form of interval.

Answer 1

We have, 

3 – 2x < 9,

Transposing 3 to RHS,

− 2x < 9 – 3

Or  − 2x < 6

Or \(\frac{-2x}{-2}\) > \(\frac{6}{-2}\)

Or x >−3

∴ When x is real, the solution is (- 3, ∞)