1. The general equation of the circle, passing through the origin and whose centers lies on x-axis can be taken as (x – h)2 + y2 = h2 where h being an arbitrary constant.
2. Simplifying (x – h)2 + y2 = h2 we get,
x2 – 2hx + h2 + y2 = h2 ⇒ x2 – 2hx + h2 = 0 _____(1)
Differentiating we get,
2x + 2y \(\frac{dy}{dx}\) – 2h = 0 ⇒ h = x + y \(\frac{dy}{dx}\)
Substituting in (1) we can eliminate h