Question

In ∆ ABC, if a = 18, b = 24, c = 30 and ∠C = 90°, find sin A and sin B.

Answer 1

\(\frac{sin\,A}{a}=\frac{sin\,B}{b}=\frac{sin\,C}{c}\)

\(\frac{sin\,A}{18}=\frac{sin\,B}{24}=\frac{sin\,90°}{30}\) 

\(\frac{sin\,A}{18}=\frac{sin\,B}{24}=\frac{1}{30}\)

\(sin\,A=\frac{18}{30}=\frac{3}{5}\)

\(sin\,B=\frac{24}{30}=\frac{4}{5}\)