For path 1:
Heat given Q1 = + 1000 J
Work done = W1(let)
For path 2:
Work done (W2) = (W1 − 100) J
Heat given Q2 = ?
As change in internal energy between two states for different paths is same.
∴ ∆U = Q1 − W1 = Q2 − W2
1000 – W1 = Q2 − (W1 − 100)
or Q2 = (1000 – 100) J
= 900 J