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in Alternating Current by (26.7k points)
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A 60µF capacitor is connected to a 110V, 60 Hz ac supply. Determine the rms value of the current in the circuit.

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Given C = 60µF = 60 × 10-6 F, Ev = 110V, ν = 60 Hz. Since Iv = \(\frac{E_v}{x_c}\)

∴ Iν = ωCEν

= 2pνCEν = 2 × 3.142 × 60 × 60 × 10-6 × 110

= 2.49A  or

Iν = 2.49V.

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