1. Fluorine and oxygen are small atoms with high value of electronegativity. Fluorine is also highly reactive in nature. It is for this reason they form compounds with noble gases.
2. No, the products of hydrolysis are XeO2F4 and XeO2F2 where the oxidation states of all the elements remain the same as it was in the reacting state.
\(Xe^{+6}F^{-1}_6 + H^{+1}_2O^{-2} \longrightarrow Xe^{+6}O^{-2}F^{-1}_4 +2H^{+1}F^{-1}\)
\(Xe^{+6}F^{-1}_6 + 2H^{+1}_2O^{-2} \longrightarrow Xe^{+6}O^{-2}_2F^{-1}_2 +4H^{+1}F^{-1}\)