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Solve the problem:

\(3 \frac{4}{5} + 2 \frac{3}{10} + 1 \frac{1}{15}\)

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1 Answer

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First convert each mixed fraction into improper fraction.

We get,

\(\Rightarrow 3 \frac{4}{5} = \frac{19}{5}\)

\(\Rightarrow 2 \frac{3}{10} = \frac{23}{10}\)

\(\Rightarrow 1 \frac{1}{15} = \frac{16}{15}\)

Then,

\(\frac{19}{5} + \frac{23}{10} + \frac{16}{15}\)

LCM of 5,10,15 = 30

Now,let us change each of the given fraction into an equivalent fraction having 30 as the denominator

\(\Rightarrow \frac{19}{5} \times \frac{6}{6} = \frac{114}{30}\)

\(\Rightarrow \frac{23}{10} \times \frac{3}{3} = \frac{69}{30}\)

\(\Rightarrow \frac{16}{15} \times \frac{2}{2} = \frac{32}{30}\)

Now,

\(= \frac{114}{30} + \frac{69}{30} + \frac{32}{30}\)
\(= \frac{114+69+32}{30}\)
\(=\frac{215}{30}\)
\(= 7 \frac{1}{5}\)

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