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+5 votes
69.3k views
in Mathematics by (9.2k points)
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A possible value of tan \((\frac{1}{4} sin^{-1} \frac{\sqrt{63}}{8})\) is

(1) \(\frac{1}{\sqrt7}\)

(2) 2√2 - 1

(3) √7 - 1

(4) \(\frac{1}{2\sqrt2}\)

by (10 points)
+1
IT IS BEST SOLUTION

2 Answers

+2 votes
by (15.1k points)
selected by
 
Best answer

Correct option is (A) \(\frac 1{\sqrt 7}\)

Let \(\sin^{-1} \left(\frac{\sqrt{63}}8\right) = \theta\)

⇒ \(\sin \theta =\frac{\sqrt{63}}8\)

So,

\(\tan \left(\frac 14 \sin^{-1} \frac{\sqrt{63}}8\right) = \tan \frac \theta 4\)

\(\cos \theta = \frac 18\)

⇒ \(2 \cos^2\frac \theta 2 - 1 = \frac 18\)

⇒ \( \cos^2\frac \theta 2 = \frac 9{16}\)

⇒ \(\cos \frac \theta 2 = \frac 34\)

⇒ \(\frac{1 - \tan^2\frac \theta 4}{1 + \tan^2\frac \theta 4} = \frac 34\)

\(\therefore \tan \frac \theta 4 = \frac 1{\sqrt 7}\)

+4 votes
by (15.8k points)

The correct option is (1) \(\frac{1}{\sqrt7}\)

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