Question

A point charge of +12 μC is at a distance 6 cm vertically above the centre of a square of side 12 cm as shown in figure. The magnitude of the electric flux through the square will be ..... x 10³Nm²/C .

Answer 1

Given Charge, Q = +12 µC

Distance, r = 6 cm

According to gauss's law, the flux of the 12-sided square is written as;

\(\phi = \frac Q{6\epsilon_0}\)

Now, on putting the given values we have,

\(\phi = \frac{12 \times 10^{-6}}{6\times 8.85 \times 10^{-12}}\)

⇒ \(\phi = 226 \times 10^3\) Nm²/C

Answer 2

From symmetry ϕ =