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0 votes
16.8k views
in Mathematics by (35.0k points)

The integral \(\int\frac{e^{3log_e{2x}+5e^{2log_e2x}}}{e^{4log_ex+5e^{3log_ex}-7e^{2log_ex}}}dx, x>0,\) is equal to :

(where c is a constant of integration)

(1) loge|x2 +5x - 7| + c

(2) 4loge|x2+ 5x- 7| + c

(3) (1/4) loge|x2 + 5x - 7| + c

(4) loge√(x2 +5x -7) + c

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1 Answer

+2 votes
by (34.6k points)

Correct option is 2

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