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in Derivatives by (36.3k points)
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Find the rate of change of the area of a circle with respect to its radius ‘r’ when r = 4 cm.

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If A is area and r is the radius of a circle, then

A = πr2

⇒ \(\frac{dA}{dr}\) = 2πr

∴ \(\begin{bmatrix} \frac{dA}{dr} \end{bmatrix}_{r=4}\) = 8π cm2/cm

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