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0 votes
10.9k views
in 3D Coordinate Geometry by (31.4k points)
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Show that the lines

\(\vec{r}=3\hat{i}+2\hat{j}-4\hat{k}+ \lambda (\hat{i}+2\hat{j}+2\hat{k});\)

\(\vec{r}=5\hat{i}-2\hat{j}+ \mu (3\hat{i}+2\hat{j}+6\hat{k});\)

are intersecting. Hence find their point of intersection.

1 Answer

+2 votes
by (30.9k points)
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Best answer

Given lines are

\(\vec{r}=3\hat{i}+2\hat{j}-4\hat{k}+ \lambda (\hat{i}+2\hat{j}+2\hat{k})\) and \(\vec{r}=5\hat{i}-2\hat{j}+ \mu (3\hat{i}+2\hat{j}+6\hat{k})\)

Its corresponding cartesian forms are

If two lines (i) and (ii) intersect, let interesting point be.

\(\Rightarrow\) \((\alpha, \beta, \gamma)\) satisfy line (i)

Also, \((\alpha, \beta, \gamma)\) will satisfy line (ii)

\(\therefore\) The value of 1 is same in both cases.

Hence, both lines intersect each other at point

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