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Evaluate each of the following:

tan-1(tan \(\frac{7\pi}6\))

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The value of tan\(\frac{7\pi}6\) = \(\frac{1}{\sqrt3}\)

∴ The question becomes tan–1\((\frac{1}{\sqrt3})\)

Let,

tan–1\((\frac{1}{\sqrt3})\) = y

⇒ tan y =\((\frac{1}{\sqrt3})\)

⇒ tan\((\frac \pi{6})=(\frac{1}{\sqrt3})\)

The range of the principal value of tan–1 is \((\frac{-\pi}2,\frac{\pi}2) \) and tan\((\frac \pi{6})=(\frac{1}{\sqrt3})\).

∴ The value of tan–1(tan\(\frac{7\pi}6\)) is \(\frac{\pi}6\).

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