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+2 votes
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in Mathematics by (31.4k points)

Let the position vectors of two points P and Q be \(3\hat{i}-\hat{j}+2\hat{k}\) and \(\hat{i}+2\hat{j}-4\hat{k},\) respectively. Let R and S be two points such that the direction ratios of lines PR and QS are (4, –1, 2) and (–2, 1, –2), respectively. Let lines PR and QS intersect at T. If the vector \(\overline {TA}\) is perpendicular to both \(\overline {PR}\) and \(\overline {QS}\) and the length of vector \(\overline {TA}\) is \(\sqrt{5}\) units, then the modulus of a position vector of A is :

(1) \(\sqrt{482}\)

(2) \(\sqrt{171}\)

(3) \(\sqrt{5}\)

(4) \(\sqrt{227}\)

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1 Answer

+2 votes
by (30.9k points)

Correct answer is (2)

dr's of normal to the plane containing P, T & Q will be proportional to :

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