Given,
A = \(\begin{bmatrix}
4 & 2 & 3 \\[0.3em]
1 & 1 &2 \\[0.3em]
3 & 0 & 1
\end{bmatrix}\), B = \(\begin{bmatrix}
1 & -1 & 1 \\[0.3em]
0 & 1 &2 \\[0.3em]
2 & -1 & 1
\end{bmatrix}\)and C = \(\begin{bmatrix}
1 & 2 & -1 \\[0.3em]
3 & 0 &1 \\[0.3em]
0 & 0 & 1
\end{bmatrix}\)
A(BC) = \(\begin{bmatrix}
-5 & 20 & -4 \\[0.3em]
-1 & 10 &-2 \\[0.3em]
-7 & 10 & -5
\end{bmatrix}\) ...(2)
From equation (1) and (2),
(AB)C = A(BC)