\(\cos^{-1}\left(\cos\frac{7\pi}{6}\right)\)\(=\cos^{-1}\left(\cos\left(2\pi+\frac{5\pi}{6}\right)\right)\)
[Formula: cos(2π – x) = cos (x), as cos has a positive vaule in the fourth quadrant. ]
\(=\cos^{-1}\left(\cos\frac{5\pi}{6}\right)\) [Formula: cos -1(cos x) = x
\(=\frac{5\pi}{6}\)