(i) -4 x \(\frac{7}{9}\) = \(\frac{7}{9}\) x -4
This is because of the use of commutative law
According to commutative law:
\(\frac{a}{b}\times \frac{c}{d}\) = \(\frac{c}{d}\times \frac{a}{b}\)
(ii) \(\frac{5}{11}\times \frac{-3}{8}\) = \(\frac{-3}{8}\times \frac{5}{11}\)
This is because of the use of commutative law
According to commutative law:
\(\frac{a}{b}\times \frac{c}{d}\) = \(\frac{c}{d}\times \frac{a}{b}\)
(iii) \(\frac{1}{2}\times (\frac{3}{4}+\frac{-5}{2})\) = \(\frac{1}{2}\times \frac{3}{4}\)+\(\frac{1}{2}\times \frac{-5}{12}\)
This is because of the use of distributive law
According to distributive law:
\(\frac{a}{b}\times \frac{c}{d}+\frac{a}{b}\times \frac{e}{f} = \frac{a}{b}\times (\frac{c}{d}+\frac{e}{f})\)
(iv) \(\frac{-4}{5}\times (\frac{5}{7}+\frac{-8}{9})=(\frac{4}{5}\times \frac{5}{7})+\frac{-4}{5}\times \frac{-8}{9}\)
This is because of the use of distributive law
According to distributive law:
\(\frac{a}{b}\times \frac{c}{d}+\frac{a}{b}\times \frac{e}{f} = \frac{a}{b}\times (\frac{c}{d}+\frac{e}{f})\)