Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
696 views
in Number System by (36.4k points)
closed by

Find the value and express as a rational number in standard from:

(i) \(\frac{2}{5}÷\frac{26}{15}\)

(ii) \(\frac{10}{3}÷\frac{-35}{12}\)

(iii) \(-6÷(\frac{-8}{17})\)

(iv) \(\frac{-40}{99}÷(-20)\)

(v) \(27÷\frac{-110}{18}\)

(vi) \(\frac{-36}{125}÷\frac{-3}{75}\)

1 Answer

+1 vote
by (38.0k points)
selected by
 
Best answer

(i) \(\frac{\frac{2}{5}}{\frac{26}{15}}\)

\(\frac{\frac{2}{1}}{\frac{26}{3}}\)

\(\frac{2}{26}\times \frac{3}{1}\)

\(\frac{3}{13}\)

 (ii) \(\frac{\frac{10}{3}}{\frac{-35}{12}}\)

\(\frac{\frac{10}{1}}{\frac{-35}{4}}\)

\(\frac{10}{1}\times \frac{-35}{4}\)

\(\frac{-8}{7}\)

 (iii) \(\frac{-6}{\frac{-8}{17}}\)

\(\frac{\frac{-6}{1}}{\frac{-8}{17}}\)

\(-6\times \frac{17}{-8}\)

\(\frac{51}{4}\)

 (iv) \(\frac{\frac{-40}{99}}{-20}\)

\(\frac{\frac{2}{99}}{\frac{1}{1}}\)

\(\frac{2}{99}\times \frac{1}{1}\)

\(\frac{2}{99}\)

 (v) \(\frac{\frac{-22}{27}}{\frac{-110}{18}}\)

\(\frac{\frac{22}{3}}{\frac{110}{2}}\)

\(\frac{22}{3}\times \frac{2}{110}\)

\(\frac{2}{15}\)

 (vi) \(\frac{\frac{-36}{125}}{\frac{-3}{75}}\)

\(\frac{\frac{36}{5}}{\frac{3}{3}}\)

\(\frac{36}{5}\times \frac{3}{3}\)

\(\frac{36}{5}\)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...