Solve for x : cos(sin^-1x)=1/2

Question

Solve for x :

\(cos(sin^{-1}x)=\frac{1}{2}\)

Answer 1

To find: value of x

Given: \(cos(sin^{-1}x)=\frac{1}{2}\)

LHS \(=cos(sin^{-1}x)\)

Therefore, \(x=\pm\frac{\sqrt{3}}{2}\)are the required values of x.