(i) \((3^{2}+2^{2})\times (\frac{1}{2})^{3}\)
⇒ \((9+4)\times \frac{1}{2^{3}}\)[Using \(a^{n}=a\times a.............n\, times\)]
⇒ \(13\times \frac{1}{8}=\frac{13}{8}\)
(ii) \((3^{2}+2^{2})\times (\frac{2}{3})^{-3}\)
⇒ \((9+4)\times (\frac{3}{2})^{3}\)[Using \(a^{-n}=\frac{1}{a^{n}}\) \(a^{n}=a\times a.............n\, times\)]
⇒ \(13\times \frac{27}{8}=\frac{351}{8}\)
(iii) \([(\frac{1}{3})^{-3}-(\frac{1}{2})^{-3}]\div (\frac{1}{4})^{-3}\)
⇒ \([(3)^{3}-(2)^{3}]\div (4)^{3}\)[Using \(a^{-n}=\frac{1}{a^{n}}\)]
⇒ [27-8]\(\div 4^{3}\)
⇒ \(19\times \frac{1}{4^{2}}\)[Using \(\frac{1}{a}\div \frac{1}{b}\)= \(\frac{1}{a}\times \frac{b}{1}\)]
⇒ \(19\times \frac{1}{4^{2}}\)= \(\frac{19}{64}\)[Using \(a^{n}=a\times a.............n\, times\)]
(iv) \((2^{2}+3^{2}-4^{2})\div (\frac{3}{2})^{2}\)
⇒ (4+9-16)\(\div (\frac{3}{2})^{2}\)[Using \(a^{n}=a\times a.............n\, times\)]
⇒ \((-3)\div \frac{9}{4}\)
⇒ \(-3\times \frac{4}{9}=-\frac{4}{3}\)[Using \(\frac{1}{a}\div \frac{1}{b}\)= \(\frac{1}{a}\times \frac{b}{1}\)]
