Given y - 2≤3x
⇒ y≤3x + 2
Consider the equation y = 3x + 2
Finding points on the coordinate axes:
If x = 0, the y value is 2 i.e., y = 2
⇒ the point on Y axis is A(0,2)
If y = 0, 0 = 3x + 2
⇒x = \(-\frac{3}{2}\)
The point on the X axis is B( \(-\frac{3}{2}\) ,0)
Plotting the points on the graph: fig.
Now consider the inequality y ≤ 3x + 2
Here we need the y value less than or equal to 3x + 2
⇒ the required region is below point A.
Therefore the graph of the inequation y ≤ 3x + 2 is fig.
figure