Correct option is A. x = 1, y = 2
We need to find the positive integral solution of the equation:
Using property of inverse trigonometry, tan(tan-1 A) = A
Applying this property on both sides of the equation,
We need to find positive integral solutions using the above result.
That is, we need to find solution which is positive as well as in integer form. A positive integer are all natural numbers.
That is, x, y > 0.
So, keep the values of y = 1, 2, 3, 4, … and find x.
| x |
\(\frac{3(1)-1}{1+3}=\frac 12\) |
\(\frac{3(2)-1}{2+3}=1\) |
\(\frac{3(3)-1}{3+3}=\frac 43\) |
\(\frac{3(4)-1}{4+3}=\frac{11}7\) |
\(\frac{3(5)-1}{5+3}=\frac 74\) |
| y |
1 |
2 |
3 |
4 |
5 |
Note that, only at y = 2, value is x is positive integer.
Thus, the positive integral solution of the given equation is x = 1, y = 2.
