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Resolve each of the following quadratic trinomials into factors:

12x2 - 17xy + 6y2

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12x2 – 17xy + 6y2

Here, coefficient of x2 = 12, coefficient of x = -17 and constant term = 6y2

We shall now split up the coefficient of middle term i.e., -17y into two parts whose sum is -17y and product is 12 x 6y2 = 72y2

Clearly,

-9y – 8y = -17y and

(-9y) (-8y) = 72y2

So, we replace middle term -17xy = - 9xy – 8xy

Thus, we have

12x2 -17xy+ 6y2 = 12x2 - 9xy - 8xy + 6y2

= 3x (4x – 3y) – 2y (4x – 3y)

= (3x – 2y) (4x – 3y)

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