Question

Solve the following equations and also verify your solution:

(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0

Answer 1

(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1) = 0

On opening the brackets we get,

x² + 5x + 6 + x² - 5x +6 - 2x² - 2x =0

-2x + 12 = 0

On dividing by -2 we get,

x - 6 = 0 x = 6

Check:

Take LHS:

(x + 2)(x + 3) + (x - 3)(x - 2) - 2x(x + 1)

On substituting x = 6

(6 + 2)(6 + 3) + (6 - 3)(6 - 2) - 12(6 + 1)

72 + 12 - 84 = 0

We got LHS=RHS