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Solve the following equations and also check your result in each case:

\(\frac{4x}9+\frac13+\frac{13x}{108}\) = \(\frac{8x+19}{18}\)

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 \(\frac{4x}9+\frac13+\frac{13x}{108}\) = \(\frac{8x+19}{18}\)

On transposing \(\frac{8x+19}{18}\) to LHS and \(\frac13\) to RHS, we get

We got LHS=RHS

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