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If y = tan–1 x, 

show that (1 + x2) \(\frac{d^2y}{dx^2}+2x\frac{dy}{dx}\)= 0.

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Best answer

Formula: –

Given: –

Y = tan–1x

Differentiating w.r.t x

\(\frac{dy}{dx}=\frac{d(tan^{-1}x)}{dx}\)

Using formula(ii)

Again Differentiating w.r.t x

Using formula(iii)

\((1+x^2)\frac{dy}{dx}+2x\frac{dy}{dx}\)=0

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