Let \(\frac{-33}{8}\) be divided by x to get \(\frac{-11}{2}\)
It can be written as,
\(\frac{-33}{8}\div\text{x}=\frac{-11}{2}\)
\(\Rightarrow\) \(\text{x}=\frac{-33}{8}\div\frac{-11}{2}\)
\(\Rightarrow\) \(\text{x}=\frac{-33}{8}\times\frac{2}{-11}\)
\(\Rightarrow\) \(\text{x}=\frac{-33\times2}{8\times-11}\)
\(\Rightarrow\) \(\text{x}=\frac{-66}{-88}=\frac{-66\times-1}{-88\times-1}=\frac{66}{88}\)
\(\Rightarrow \) \(\text{x}=\frac{66}{88}=\frac{66\div22}{88\div22}=\frac{3}{4}\)
Hence, it should be multiplied by is \(\frac{3}{4}\)
