\(\frac{8}{-15}=\frac{8\times-1}{-15\times-1}=\frac{-8}{15}\)
And,
\(\frac{4}{-3}=\frac{4\times-1}{-3\times-1}=\frac{-4}{3}\)
\(\Rightarrow\) \(\frac{8}{-15}+\frac{4}{-3}=\frac{-8}{15}+\frac{-4}{3}\)
\(\Rightarrow\) \(\frac{-8\times3+(-4)\times15}{45}\)
\(\Rightarrow\) \(\frac{-24-60}{45}\)
\(=\frac{-84}{45}=\frac{-84\div3}{45\div3}=\frac{-28}{15}\)