Given,
Amount = Rs.453690
Time = 2 years
Rate = 6.5 % p.a
Let principal = Rs. P
So,
A \(={P}[({1}+\frac{R}{100})^T]\)
\(={P}[({1}+\frac{6.5}{100})^2]\) = 453690
\(={P}\times\frac{213}{200}\times\frac{213}{200}\) = 453690
\(={P}=\frac{453690 \times 200 \times 200}{213\times213}\) = Rs. 400000
Hence ,
Principal = Rs. 400000