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A ladder, 5 meter long, standing on a horizontal floor, leans against a vertical wall. If the top to the ladder slides down wards at the rate of 10 cm/sec, then find the rate at which the angle between the floor and ladder is decreasing when lower end of ladder is 2 meters from the wall.

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Given that \(\frac{dh}{dt}\) = -1.0m/sec. We have to find \(\frac{dθ}{dt}\) when h = 2m

Differentiating (1) with respect to t, we get

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