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in Continuity and Differentiability by (27.4k points)
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Find the value of the constant k so that the given function is continuous at the indicated point :

\(f(x) = \begin{cases}kx^2&, \quad x≥1\\4 &, \quad x<1\\\end{cases} \) at x = 1

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Best answer

Given : 

f(x) is continuous at x = 1 

If f(x) to be continuous at x = 1,

then,

f(1) = f(1)+ = f(1)

⇒ k(1–0)2 

⇒ k ....(2) 

Since, 

f(x) is continuous at x = 1 & also 

from (1) & (2),

∴ k = 4

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