(i) On rearranging we get, \((\frac{1}{2}a-3b)(3b+\frac{1}{2}a)(\frac{1}{4}a^2+9b^2)\)

(ii) On rearranging we get, \((m+\frac{n}{7})^3(m-\frac{n}{7})\)

(iii) On rearranging we get, \((\frac{x}{2}-\frac{2}{5})(\frac{2}{5}-\frac{x}{2})\) - x2 + 2x


(iv) Using the idendity, (a+b)(a - b) = a2 - b2
On rearranging we get,

(v) Taking x as common factor, we write,

(vi) On Reaaranging we get,
