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+1 vote
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in Continuity and Differentiability by (27.4k points)
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If \(f(x) = \begin{cases} \frac{1-cosx}{x^2} ,& x ≠{0}\\ k, & x={ 0} \end{cases} \) is continuous at x = 0, find k.

1 Answer

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Best answer

(i)  \(\lim\limits_{x \to 0}\frac{sinx}{x}\) = 1

(ii) A function f(x) is said to be continuous at a point x=a of its domain, if 
\(\lim\limits_{x \to a}f(x)\) = f(a) 

\(f(x) = \begin{cases} \frac{1-cosx}{x^2} ,& x ≠{0}\\ k, & x={ 0} \end{cases} \)

Now,

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