If y = log((1 - x^2)/(1 + x^2)), then dy/dx = A. 4x^3/1 - x^4 B. 1/4 - x^4 C. 1/4 - x^4 D. 4x^3/1 - x^4

Question

If y = log\(\Big(\cfrac{1-\text x^2}{1+\text x^2}\Big),\) then \(\cfrac{dy}{d\mathrm x} \) =

A. \(\cfrac{4\text x^3}{1-\text x^4}\)

B. \(-\cfrac{4\text x}{1-\text x^4}\)

C. \(\cfrac{1}{4-\text x^4}\)

D. \(\cfrac{4\text x^3}{1-\text x^4}\)

Answer 1

Correct option is  B. \(-\cfrac{4\text x}{1-\text x^4}\) 

(Using quotient rule)