Given,
External dimensions of box = 36cm × 25cm × 16.5cm
Thickness of iron = 1.5 cm
Inner dimensions of box = [(36 - 3) × (25 - 3) × (16.5 - 1.5)]
=33cm × 22cm × 15cm
Volume of iron used = external volume – internal volume
= 36 × 25 × 16.5 – 33 × 22 × 15 = 3960 cm3
∵ weight of 1 cm3 iron = 15 gm (given)
∴ weight of 3960 cm3 iron = 3960×15 = 59400 gm = 59.4 kg