Question

Find the value of p for the following distribution whose mean is 16.6

x:	8	12	15	p	20	25	30
y:	12	16	20	24	16	8	4

Answer 1

X	y	yx
8	12	96
12	16	192
15	20	300
p	24	24p
20	16	320
25	8	200
30	4	120
	N = 100	\(\sum\)yx = 24p + 1228

Given,

Mean = 16.6

\(\frac{\sum yx}{N}=16.6\)

\(\frac{24p+1228}{100}=16.6\)

24p + 1228 = 1660

24p = 1660 – 1228

24p = 432

p = \(\frac{432}{24}=18\)