Question

In Fig. two congruent circles with centres O and O’ intersect at A and B. If ∠AO’B = 50°, then find ∠APB.

Answer 1

∠AO'B = 50° 

Since, 

both the triangle are congruent so their corresponding angles are equal. 

∠AOB = AO'B = 50°

Now,

∠APB = \(\frac{AOB}{2}\)

∠APB = \(\frac{50}{2}\)

= 25°